GrandCaravanSE
Active Member
Suppose you are firing a cannonball at a target 726 m away. Your cannon fires its ammo at 89m/s. what angle(s) should you place the cannon's barrel?
About 270 degrees... up your butt?
well, 89cos(theta) = 726/t
and 89sin(theta) = 4.9t
a few simple algebraic tricks later, and we find that the angle must be 31.95 degrees
@89M/s, it wold be hard pressed to even come close to the target.
Wrong, but nice try.
you really know you alge/phys, now did you do the formula, or did you do it the long way with algebra?
well, I solved both the above equations for t = F(theta) and t = G(theta)
then I set y = F(theta) - G(theta), and found where y = 0.