a13antichrist
New Member
AnomalousEntity said:I think the odds were somthing like .00000000000001 in 10 Trillion.
Let's take your word on this for a second, OK? If the odds of any given planet having the right conditions, etc etc, were that number, i.e, 0.00000000000001x10^-13 P=0.000000000000000000000000001, then the probability of that planet NOT having those conditions is 1-P = 0.999999999999999999999999999. Now, the Probability of any two planets chosen at random NOT having the right conditions etc is
P1 x P2 = 0.999999999999999999999999999 x 0.999999999999999999999999999
=> 0.999999999999999999999999998.
For three planets?
P1 x P2 x P3 = 0.999999999999999999999999999 x 0.999999999999999999999999999 x 0.999999999999999999999999
=> x 0.999999999999999999999999997
So, the Probability [ P(x) ] of there NOT having the right conditions on Z number of planets is (0.999999999999999999999999999)^Z.
But the universe is infinite. So to find the P() that these conditions did not appear on ANY planet anywhere in the universe, we need to take
Code:
lim (0.999999999999999999999999999)^Z
z -> oo
, which is of course 0. Therefore, it is CERTAIN, that no matter how small the probability of any given planet having those right conditions, in an infinite universe with an infinite number of planets, there WILL be at least one planet that has the right conditions for bearing life.
Q.E.D